A solid cube of metal each of whose sides measures 2.2 cm is melted to form a cylindrical of the wire of radius 1 mm. Find the length of the wire so obtained.
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Volume of the cube=2.2×2.2×2.2 cubic. cm.
Now, let the length of the wire obtained/formed be l.
Therefore, the volume of wire =πr^2l
=(22/7)×(1×1)×l cubic mm
=(22/7)×(0.1×0.1)×l cubic cm
As the same cube is used for the wire, their volume should be equal.
=>(22/7)×(0.01)×l =2.2×2.2×2.2
=>l =2.2×2.2×2.2(7/22)×100
=>l =338.8 cm
=>l =33.88m [Answer]
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Now, let the length of the wire obtained/formed be l.
Therefore, the volume of wire =πr^2l
=(22/7)×(1×1)×l cubic mm
=(22/7)×(0.1×0.1)×l cubic cm
As the same cube is used for the wire, their volume should be equal.
=>(22/7)×(0.01)×l =2.2×2.2×2.2
=>l =2.2×2.2×2.2(7/22)×100
=>l =338.8 cm
=>l =33.88m [Answer]
Hope this helps. Follow me for more answers. Comment for any clarifications please. Thanks!
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Answer:
Answer is 338.8 cm
Answer is 338.8 cm Hope it help you
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