A solid cube whose edges are 4 cm each has been cut by a plane that bisects the three edges meeting at a corner and the smaller part is removed.
What is the surface area of removed part ?
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Given:
A geometrical figure = Cube
Side of the cube = 4cm
Total edges where the cube bisects = 3
To find:
Total Surface Area of the removed part of cube
Solution:
As the side of the cube is 4 - when it is cut it becomes = 4/2 = 2.
Therefore,
Surface area = 3 × 4 × 4 + 3 ( 4 × 4 - 1/2 × 2 × 2 ) + √3/4 ( 2√2)²
= 48 + 32 + 2√3
= 80 + 2√3
Answer: The surface area of removed part is 80 + 2√3.
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