A solid cuboid of iron with dimensions 53 cm × 40 cm × 15 cm is melted and recast into a cylindrical pipe. The outer and inner diameters of pipe are 8 cm and 7 cm respectively. Find the length of the pipe.
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Answer:
Volume of cuboid = 53 × 40 × 15
= 31800 cm³
Volume of hollow-cylinder = πh (R² - r²)
= 22/7 × h (4² - 3.5²)
= 22/7 × h (16 - 12.25)
= 22/7 × h * 3.75
31800 = 22/7 × h × 3.75
222600 = 22 × h × 3.75
222600 = 82.5 × h
h = 222600/82.5
= 2698.18 cm
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