Question

A solid cuboid of iron with dimensions 53cm into 40 cm into 15 cm is melted and recast into a cylindrical pipe the outer and inner diameter of the pipe are 8 cm and 7 cm respectively find the length of 5

Answer 1

↑ Here is your answer ↓
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Volume of cuboid = 53 x 40 x 15
                             = 31800 cm³

Volume of hollow-cylinder = πh (R² - r²)
                                          = 22/7 * h (4² - 3.5²)
                                          = 22/7 * h (16 - 12.25)
                                          = 22/7 * h * 3.75

31800 = 22/7 * h * 3.75

222600 = 22 * h * 3.75
222600 = 82.5 * h

h = 222600/82.5
   = 2698.18 cm

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Glad to help you.

@EmadAhamed

Answer 2

Answer:

Volume of cuboid = 53 × 40 × 15

                            = 31800 cm³

Volume of hollow-cylinder = πh (R² - r²)

                                         = 22/7 × h (4² - 3.5²)

                                         = 22/7 × h (16 - 12.25)

                                         = 22/7 × h * 3.75

31800 = 22/7 × h × 3.75

222600 = 22 × h × 3.75

222600 = 82.5 × h

h = 222600/82.5

  = 2698.18 cm