Question

A solid cylinder has a total surface area of 462 sp. cm.
It's curved surface area is one third of its total surface area, find the height. ​

Answer 1

Answer:

TOTAL SURFACE AREA OF THE CYLINDER(TSA)=462CM²

CURVED SURFACE=1/3 OF TSA

=1/3 X 462

=154CM²

AREA OF EACH CIRCLE=(462-154)/2

=154CM²

PI*R²=154

R²=49

R=7

2PI*R*H=154

H=154*7/22*7

H=3.5

VOLUME=PI*R²*H=22/7*49*35/10

VOLUME=539CM³

Answer 2

$\huge{\mathfrak{\red{Answer}}}$

Curved surface area = total surface area / 3.

Curved surface area = 462/3 = 154.

Rest of area = 462 - 154 = 308.

$\longrightarrow$2πr^2 = 308.

$\longrightarrow$r^2 = 308 x 7 / 44 = 49.

$\longrightarrow$r = 7.

2πrh = 154.

h = 154 / 2 x 22 = 7/2.