A solid cylinder has T.S.A 462 cm its c.s.a is 1/3 of its T.s.a .find volume( use π=22/7)
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Answered by
3
TOTAL SURFACE AREA OF THE CYLINDER(TSA)=462CM²
CURVED SURFACE=1/3 OF TSA
=1/3 X 462
=154CM²
AREA OF EACH CIRCLE=(462-154)/2
=154CM²
PI*R²=154
R²=49
R=7
2PI*R*H=154
H=154*7/22*7
H=3.5
VOLUME=PI*R²*H=22/7*49*35/10
VOLUME=539CM³
CURVED SURFACE=1/3 OF TSA
=1/3 X 462
=154CM²
AREA OF EACH CIRCLE=(462-154)/2
=154CM²
PI*R²=154
R²=49
R=7
2PI*R*H=154
H=154*7/22*7
H=3.5
VOLUME=PI*R²*H=22/7*49*35/10
VOLUME=539CM³
Answered by
3
CSA =1/3TSA
2πrh = 1/3×2πr(h+r)
h= 1/3*(h+r)
3h =h+r
2h =r
now TSA = 2πr(h+r)
462 = 2*22/7*2h(h+2h)
462×7/22*2*2 =3h^2
21*7/2*2*3=h^2
h=7/2
h=7/2 or r=7
vol = πr^2h =22/7 (*7*7*7/2)= 539 cubic cm
2πrh = 1/3×2πr(h+r)
h= 1/3*(h+r)
3h =h+r
2h =r
now TSA = 2πr(h+r)
462 = 2*22/7*2h(h+2h)
462×7/22*2*2 =3h^2
21*7/2*2*3=h^2
h=7/2
h=7/2 or r=7
vol = πr^2h =22/7 (*7*7*7/2)= 539 cubic cm
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