Question

a solid cylinder has total surface area of 462 CM square its curved surface area is one third of its total surface area find the radius and height of the cylinder

Answer 1

TOTAL SURFACE AREA OF THE CYLINDER(TSA)=462CM²
CURVED SURFACE=1/3 OF TSA
=1/3 X 462
=154CM²
 AREA OF EACH CIRCLE=(462-154)/2
=154CM²
PI*R²=154
R²=49
R=7
2PI*R*H=154
H=154*7/22*7
H=3.5
VOLUME=PI*R²*H=22/7*49*35/10
VOLUME=539CM³

Answer 2

Answer:

r=7/2

h=7/4

Step-by-step explanation:

TSA=462 cm²

2πr(r+h)=462 cm²

CSA=TSA/3

=462/3

=154 cm²

2πrh=154→α

2πrh:154::2πr(r+h):462

2πrh x 462=2πr(r+h) x 154

→[2πr(r+h)]/2πrh = 462/154

→r+h=3h

→r=2h

α→2πrh=154

→2x2hxhx22/7=154

→h²=(154x7)/(2x2x22)

→h²=49/4

→h=7/4

r=2h

r=2x7/4

→r=7/2