Math, asked by mehakaggarwal5260, 1 year ago

A solid cylinder is of height 15 cm and diameter 7 cm. Two equal conical holes of radius 3 cm and height 4 cm are cut off, one from each circular end. find the surface area of the remaining solid

Answers

Answered by rohitkumargupta
13
HELLO DEAR,





Given:-

 Height of the cylinder (H) = 14 cm



Diameter of the base of cylinder = 7 cm



radius of the base of cylinder (R)= 7/2 cm




Surface area of cylinder = 2πR(R+H)



=> 2x (22/7)x(7/2)(7/2 + 14)



=> 2 x 11x (35/2)


=> 385 cm2


Now Radius of base of cone (r) = 3 cm




height of cone (h) = 4 cm



Surface area of cone = πr(r + √(h2 + r2))



=> (22/7)x3x(3 + √(42 + 32) )




=> (22/7)x3x(3 + 5)



=> (22x3x8)/ 7



=> 528 / 7


=> 75.43 cm2


Hence the surface area of the remaining
solid

 = >Surface area of cylinder


– Surface area of 2 cones


=> 385 cm2 – 2x75.43 cm2


=> 385 cm2 – 150.86 cm2


=> 234.14 cm2

I HOPE ITS HELP YOU DEAR,
THANKS


rohitkumargupta: ya
rohitkumargupta: its ok
rohitkumargupta: red wale pe thnx bolo
mehakaggarwal5260: If there would be any I will ask you
rohitkumargupta: ya sure
rohitkumargupta: buy inbox
rohitkumargupta: but
rohitkumargupta: me
rohitkumargupta: no here
mehakaggarwal5260: solid=ar. of cylinder+ar. of cone
diameter of cylinder=7cm
radius=7/2cm
radius of conical hole=3cm
height=4cm
so l=h^2+r^2(hole root)
l=(4)^2+(3)^2(hole root)
l=16+9(hole root)
l=25(hole root)
root of 25 is 5 so,
l=5cm
put it in formula,
2*22/7*7/2*15+2(22/7*3*5) (because there are two conical holes)
330+2(22/7*3*5)
330+2(330/7)
330+660/7
2310+660/7
2970/7cm^2
Answered by muskansingh52
2

I hope this is correct answer..............

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