Question

A solid cylinder is summoned by a solid cone and a solid hemisphere in two ends. The radius and length of the cylindrical part are 4 cm and 10 cm respectively. If totwl length of the solid is 17 cm, find the volume and surface area of the solid.


I NEED FULL EXPLANATION!
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Answer 1

Question-:

A solid cylinder is summoned by a solid cone and a solid hemisphere in two ends. The radius and length of the cylindrical part are 4 cm and 10 cm respectively. If totwl length of the solid is 17 cm, find the volume and surface area of the solid.

Answer-:

For all figures,

r=7 cm

l (slant height)= h (height of cylinder)=4 cm

T.S.A of the figure= C.S.A of Cone+C.S.A of cylinder +C.S.A of hemisphere.

CSA of cone: πrl=(3.14)×(7cm)×(4cm)=87.92 cm2

CSA of cylinder: 2πrh=(2)×(3.14)×(7cm)×(4cm)=175.84 cm2

CSA of hemisphere: 2πr2=(2)×(3.14)×(7cm)2=307.72 cm2

Adding all: TSA of figure=  571.48 cm2

Request-:

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Answer 2

Answer:

we need to know that solid is formed by the combinations of cone, cylinder, hemisphere

so we need to calculate seperately for volume and surface area

Step-by-step explanation:

for volume:

1)cone--->V=1/3hπr²

2)cylinder--->V=πr^2h

3)hemisphere---->(2/3)πr^3

so the total volume of solid is {vol of cone + vol of cylinder+vol of hemisphere}

on solving by using the formulas as above mentioned we get

volume of solid is (656π)/3

for surface area:

1)cone---->total surface area--->πr(r+sqrt(h^2+r^2))

2)cylinder--->2πrh+2πr^2

3)hemisphere---->3πr^2

so the total surface area of solid is {surface area of cone + surface area of cylinder+surface area of hemisphere}

on solving by using the formulas as above mentioned we get

surface area of solid is 196π