A solid cylinder of base of 36 cm diameter is melted and recast into a solid cone of height 24 cm and radius of the base 36 cm. Height of the cylinder is
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let height of cylinder =H
volume of cylinder =πr^2H
=π(18)^2H
volume of cone =πR^2h/3
=π(36)^2 x 24/3
because cylinder melt to formed cone
hence,
vol of cylinder= vol of cone
π(18)^2H=π(36)^2 x 8
(18)^2 H=(36)^2 x 8
H=(36 x 36 x 8)/(18 x 18)
=32cm
volume of cylinder =πr^2H
=π(18)^2H
volume of cone =πR^2h/3
=π(36)^2 x 24/3
because cylinder melt to formed cone
hence,
vol of cylinder= vol of cone
π(18)^2H=π(36)^2 x 8
(18)^2 H=(36)^2 x 8
H=(36 x 36 x 8)/(18 x 18)
=32cm
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