Question

a solid cylinder of length l, diameter d and specific gravity 0.6

Answer 1

A solid cylinder of length L, diameter D and specific gravity 0.6 floats in neutral equilibrium in water with its axis vertical. What is the ratio  ...

Answer 2

For neutral equilibrium, GM = 0 (M coinciding with G)

Hence,

               $\frac { L }{ D } \quad =\quad \frac { 1 }{ \sqrt { 8S\left( 1\quad -\quad S \right) } }$

Given specific gravity = 0.6  

               $\frac { L }{ D } \quad =\quad \frac { 1 }{ \sqrt { 8\quad \times \quad 0.6\quad \left( 1\quad -\quad 0.6 \right) } }$

               $=\quad \frac { 1 }{ \sqrt { 8\quad \times \quad 0.6\quad \times \quad 0.4 } }$

               $\frac { L }{ D } \quad =\quad \frac { 1 }{ 8\sqrt { 0.03 } }$