A solid cylinder of mass 20 kg rotates about its axis with angular speed 100 rad/s. The radius of the cylinder is 0.25m. The K.E. associated with the rotation of the cylinder is(a) 3025 J(b) 3225 J(c) 3250 J(d) 3125 J
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✔✔CORRECT OPTION IS (D) ✔✔
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Answer:
D) 3125J
Explanation:
Mass of cylinder (M) = 20 Kg (Given)
Radius of its (R) = 0.25 m (Given)
Angular speed (w) = 100 rad/s (Given)
Moment of inertia of solid cylinder is given as (I) = (1/2)MR²
= (1/2) × 20× (0.25)²
= 0.625 kg.m²
Kinetic energy associated with the rotation of the cylinder is given by the equation -
K.E = (1/2)Iw²
= (1/2) × 0.625 × (100)²
= 3125 joule
Thus, The K.E. associated with the rotation of the cylinder is 3125J
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