Question

A solid cylinder of mass 20 kg rotates about its axis with angular speed 100 rad/s. The radius of the cylinder is 0.25m. The K.E. associated with the rotation of the cylinder is(a) 3025 J(b) 3225 J(c) 3250 J(d) 3125 J

Answer 1

✔✔CORRECT OPTION IS (D) ✔✔

Answer 2

Answer:

D) 3125J

Explanation:

Mass of cylinder (M) = 20 Kg (Given)

Radius of its (R) = 0.25 m (Given)

Angular speed (w) = 100 rad/s (Given)

Moment of inertia of solid cylinder is given as (I) = (1/2)MR²

= (1/2) × 20× (0.25)²

= 0.625 kg.m²

Kinetic energy associated with the rotation of the cylinder is given by the equation -

K.E = (1/2)Iw²

= (1/2) × 0.625 × (100)²

= 3125 joule

Thus, The K.E. associated with the rotation of the cylinder is 3125J