Question

A solid cylinder of mass 20kg has length 1 m and radius 0.2 m. Then its moment of inertia
(in kg-m²) about its geometrical axis is-

​

Answer 1

The moment of inertia of solid cylinder is 0.4 kg-m².

Explanation:

Given that,

Mass of solid cylinder = 20 kg

Length = 1 m

Radius = 0.2 m

Suppose we find the moment of inertia of the solid cylinder

We need to calculate the moment of inertia of the solid cylinder

Using formula of moment of inertia

I=\dfrac{1}{2}MR^2

Put the value into the formula

I=\dfrac{1}{2}\times20\times(0.2)^2

Hence, The moment of inertia of solid cylinder is 0.4 kg-m².

Answer 2

$\huge\underbrace\mathfrak \red{ANSWER }$

The moment of inertia of solid cylinder is 0.4 kg-m².

Explanation:

Given that,

Mass of solid cylinder = 20 kg

Length = 1 m

Radius = 0.2 m

Suppose we find the moment of inertia of the solid cylinder

We need to calculate the moment of inertia of the solid cylinder

Using formula of moment of inertia

I=$\dfrac{1}{2}MR^2$

Put the value into the formula

I=$\dfrac{1}{2}\times20\times(0.2)^2$

Hence, The moment of inertia of solid cylinder is 0.4 kg-m².

HOPE SO IT WILL HELP...

PLEASE MARK IT AS BRAINLIST....