Question

A solid cylinder of mass 50 kg and radius 0.5 m is free to rotate about the horizontal axis. A massless string is wound round the cylinder with one end attached to it and other hanging freely. Tension in the string required to produce an angular acceleration of 2 revolutions s⁻² is :(a) 25 N(b) 50 N(c) 78.5 N(d) 157 N

Answer 1

Answer:

D) 157N

Explanation:

Mass of the cylinder m=50kg (Given)

Radius of the cylinder r =0.5m  (Given)

α = 2 rev/s²

Torque by Tension in string = T × R= T × 0.5 = T/2 N-M

= T = Iα = T/2 = Iα

= T/2 = 50 × (0.5)² × 4π/2

T = 157N

Therefore, Tension in the string required to produce an angular acceleration of 2 revolutions s⁻² is 157N.