Question

A solid cylinder of mass m and radius r rolls without slipping down on inclined plane of length l and height h the speed of centre of mass is

Answer 1

Answer:

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T.E.=Rot.K.E.+Trans.K.E.

Rot.K.E.=(1/2)Iw²=(1/2)(2/5)Mr²w²=(1/5)Mv²

Tans.K.E.=(1/2)Mv²

So Total energy=(1/2)Mv²+(1/5)Mv²=(7/10)Mv².

So the % of R.K.E. is(1/5)Mv²/{(7/10)Mv²}×100

=(2/7)×100=28.57%.Ans