Question

A solid cylinder of radius 3 cm
and height 8 cm is melted and formed into a cone of radius 6 cm. Find the height of the
cone.

pls answer as soon as possible:)​

Answer 1

height = 6cm

pls mark me brainliest and follow me

Answer 2

$\LARGE{\bf{\underline{\underline{GIVEN:-}}}}$

• The radius of cylinder (r₁) = 3 cm.
• The height of cylinder (h₁) = 8 cm.
• The radius of cone (r₂) = 6 cm.

$\LARGE{\bf{\underline{\underline{TO:FIND:-}}}}$

• The height of cone (h₂)

$\LARGE{\bf{\underline{\underline{SOLUTION:-}}}}$

The solid cylinder was melted into a cone, so the volume remains the same.

$\to \sf V_{cylinder} = V_{cone}$

$\sf \to\pi (r_1)^2h_1=\dfrac{\pi (r_2)^2h_2}{3}$

Substitute the values.

$\sf \to\not{\pi} 3^2 \times 8=\dfrac{\not{\pi} 6^2 \times h}{3}$

$\sf \to 72= 36\times h$

$\sf \to h=\dfrac{72}{12}$

$\to \sf{\red{h=6 cm.}}$

HEIGHT :- 6 cm.

FORMULAS USED:

$\sf V_{cone}=\dfrac{\pi r^2h}{3}$

$\sf V_{cylinder}=\pi r^2h$

MORE FORMULAS:

$\sf V_{sphere}=\dfrac{4}{3} \pi r^3$

$\sf V_{cuboid}=l \times b \times h$

$\sf V_{cube}= a^3$

$\sf V_{pyramid}=\dfrac{l \omega h}{3}$

$\sf V_{prism}=Bh$