Question

a solid cylinder starts falling from height H on an inclined plane at some instant t, the ratio of its rotational kinetic energy and the total kinetic energy would be

Answer 1

hey sis here is your answer

Rotational kinetic energy is

(KE)r =1/2 Iw2 =1/2{1/2MR2}

=1/4 MR2w2 where(I=1/2MR2)

Where Mis the mass of the disc and R radius ,

Translational kinetic energy is

(KE)r = 1/2 Mv2 =1/2 m(Rw)2 =1/2MR2 w2 where (V=Rw)

Total energy KE =(KE)r +(KE)r =3/4Mr2 W2

Hence (KE)r/KE =2/3


hope it helps you

Answer 2

Answer:

1:3

please mark brainliest