Math, asked by Kanishkasharma6336, 2 months ago

A solid cylinder whose height is 12 cm and its base radius is 10.5 cm is melted to form a wire of diameter 2 mm what will be the length of wire so obtained?

Answers

Answered by NIRANJANl
1

Answer:

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Answered by arpitaverma604
3

Answer:

13200cm²

Step-by-step explanation:

Given....

For the cylinder .

H = 12cm

R = 10.5cm

For the wire which is in a cylindrical shape..

D = 2mm

R = 2mm/2

=1mm

Now convert it in cm

= 1mm/10

= 0.1cm

Th find length .  

volume of cylinder = volume of wire

Now convert it in cm .

\pi r^{2} h = \pi r^{2} h

\frac{22}{7} × 10.5^{2} × 12 = \frac{22}{7} × 0.1² × h

cancel   \pi

10 .5 × 10.5 × 12 = 0.1 × 0.1 × h

1323 = 0.1 × h

\frac{1323}{0.01} = h

13200cm³ = h

Therefore,  length of wire is 13200cm³

hope it helps you....

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