Question

A solid cylinder whose height is 12cm and its base radius is 10.5 cm, a wire of diameter 2mm. what will be length of the wire so obtained?

Answer 1

Given.......

For the cylinder ...
H = 12cm
R = 10.5cm

For the wire which is in a cylindrical shape..
D = 2mm
R = 2mm/2
=1mm

Now convert it in cm
= 1mm/10
= 0.1cm
Th find lenght.....

vol of cylinder = vol of wire

Now convert it in cm ...
$\pi \: {r}^{2} h \: = \pi \: {r}^{2} h \\ \\ \frac{22}{7} \times 10.5 \times 10.5 \times 12 = \frac{22}{7} \times 0.1 \times 0.1 \times h \\ \\ cancell \: \pi \\ \\ 10.5 \times 10.5 \times 12 = 0.1 \times 0.1 \times h \\ \\ 1323 = 0.01 \times h \\ \\ \frac{1323}{0.01} = h \\ \\ 13200 {cm}^{3} = h \\ \\ therefore \: length \: of \: the \: wire \: is \: 13200 \: {cm}^{3} \\ \\ \\ thnx.....$