Question

a solid element forms gaseous oxide without change in volume if the vapour density of the oxide is 32 what is the equivalent weight of the solid element​

Answer 1

Answer:

i don't know but i will tell u

Explanation:

Here it is

2M+O

2

→2MO

Molecular weight of gaseous oxide =2× vapour density

=2×32=64

∴ So molar mass of M=64−2×16=32

So M should be Sulphur (S)

∴ Equivalent weight of S= 32/4

And yeah please mark me as BRAINEIST