A solid floats with (1/4)th of its volume above the surface of water. Calculate the density of solid.....
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A solid floats with (1/4)th of its volume above the surface of water. Calculate the density of solid.
Good question,
Here is your perfect answer!
Let V be volume and p be density of solid.
W = Vpg
Volume inside water = V - V/4
= 3V/4
Weight displaced by immersed portion = 3V/4 × 10³ × g
Using principle of floatation ;
Vpg = 3V/4 × 10³ ×g
Hence p = 3/4×10³
= 750 kg/m³
This is our answer!
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Heya ____
Solution is given here ____
Let the volume = v
Density of solid = p
So.... w = vpg
Volume inside water = 3v/4
Weight displaced by immersed portion is 3v/4*10^3*g
By using principle of floatation :-
vpg = 3v/4*10^3*g
p = 3v/4*10^3
So.... 750 kg /m^3 .... Ans..
Thank you
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