Question

A solid floats with 1/5th of its volume above water. Find density of the solid.​

Answer 1

Let V be the volume and d be the density of the solid then weight of the body =Vdg.

Volume of solid body inside water =V−  

4

V

​  

=  

4

3V

​  

 

Weight of water displaced by immersed portion of the body

=  

4

3V

​  

×10  

3

×g

∴ By the principle of floatation,

Vdg=  

4

3V

​  

×10  

3

g

⇒d=  

4

3

​  

×10  

3

=750kgm  

−3

.