A solid floats with 1/5th of its volume above water. Find density of the solid.
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1200 f will be there density
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Let V be the volume and d be the density of the solid then weight of the body =Vdg.
Volume of solid body inside water =V−
4V= 43VWeight of water displaced by immersed portion of the body
= 43V×10 3×g∴ By the principle of floatation,Vdg= 43V ×10 3g⇒d= 43×10 3 =750kgm −3
Explanation:
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