A solid frustum is of height 8 cm. If the radii of its lower and upper ends are 3 cm and 9 cm respectively, then its slant height is
(a)15 cm
(b)12 cm
(c)10 cm
(d)17 cm
Answers
Answered by
18
Answer:
The Slant height of a frustum is 10 cm.
Among the given options option (c) 10 cm is the correct answer.
Step-by-step explanation:
Given :
Height of a frustum, (h) = 8 cm
upper Radius, R = 9 cm
Lower Radius, r = 3 cm
Slant height of a bucket , l = √(R - r)² + h²
l = √(9 - 3)² + 8²
l = √6² + 64
l = √(36 + 64)
l = √100
l = 10 cm
Slant height of a frustum,l = 10 cm
Hence, the Slant height of a frustum is 10 cm.
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Answered by
3
10cm
l^2 = h^2+(r2-r1)^2
l =√{8^2+(9-3)^2}
l = √64+36
l= √100= 10
l^2 = h^2+(r2-r1)^2
l =√{8^2+(9-3)^2}
l = √64+36
l= √100= 10
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