Physics, asked by vickythakur9536, 6 hours ago

A solid glass sphere of radius 10 cm and refraction index 1.5 is placed in water of refractiveindex 4/3 A point mark P is at distance 5 cm from the centre. This point mark is viewed along thediameter of the sphere as shown in the figure.A) The image of point object P seen by observer 0, is 2 cm from itself24B) The image of point object P seen by observer O, is at cm from itself17C) The image of point object P seen by observer O, is at a distance 16 cmD) The image of point object P seen by observer O, is at a distance 26 cm from it self​

Answers

Answered by waseemrehim4
0

Explanation:

We will have single surface refractions successsively at the four surfaces S1,S2,S3andS4. Do not forget to shift origin to the vertex of respective surface.

Refractive at first surface S1: Light travels from air to glass.

1.5υ1−1∞=(1.5−1)(+10)

υ1=30cm

First image is object for the refractioni at second surface.

For refraction at surface S2: Light travels from glass to air.

1.5υ2−1.5(+25)=1−1.5(+5)

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