Question

A solid has 5 faces and 9 edges find its vertices​

Answer 1

Answer:

We know from Euler’s formula for polyhedra that F+V=E+2, so there must be (9–5)+2 = 6 vertices. That should give you an idea of what kind of shape this could be. Take two triangles (three edges each) and then join the vertices of the triangles with three more edges. That’s a nine-edged, five faced object (would probably be easiest to envision a prism shape, but it doesn’t have to be.)

Answer 2

Answer:

Vertices = 6

Step-by-step explanation:

Using euler's formula

{Euler's formula = (Faces + vertices = Edges +2)}Euler

′

sformula=(Faces+vertices=Edges+2)

Number of faces = 5

Number of edges = 9

Number of vertices = V

According to euler's formula

5 + V = 9 + 2

5+V = 11

V = 11 - 5

V = 6

So the the solid has six vertices

Explanation:

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