Question

A solid has a structure in which A atoms are located at the cube corners of the unit cell,B atoms are located at the cube edges of unit cell and the c atoms at the body centre.Formula of the compound


please solve this problem in details ​

Answer 1

number of A atom =

$1 \div 8 \times 8 = 1$

number of B atom =

$1 \div 4 \times 12 =3$

C is at the center so number of C atom is

1

formula of compound is AB3C

Answer 2

Answer:

CAB3

Explanation:

C= body centered. = 1

B= cube edges. = 1/4*12= 3

A= cube corner atoms =1/8*8=1

so the answer is CAB3

I Hope it will help u....