Question

A solid has the dimensions of 10cm×5cm×5cm.what is the upthrust on it when

completely immersed in a liquid of density 1.1gcm-3?​

Answer 1

Explanation:

so upthrust can be calculated by

V× density of liquid × g

now v = volume of object

so here = 10 ×5×5 = 250 cm^3

density = 1.1g/cm^3

g = 9.8m/s^2

so now 1g =1/1000 kg

so 1.1 g = 1.1/ 1000 = 0.0011 kg

now density will be

0.0011 kg /cm^3

so upthrust will be

250 cm^3 × 0.0011kg/cm^3 × 9.8 m/s^2

= 2.695 kg m/s^2 = 2.695 N answer