A solid hemisphere of diameter 16cm is placed on the top of a solid cylinder whose diameter is also 16cm. The height of the cylinder is 20cm. Find the common CG of the combined solid from the base of the cylinder.
Answers
Answered by
0
Answer:
hainsml kshkajnsbian oksms
Answered by
0
Answer:
Let r cm be the radius and h cm the height of the cylinder. Then,
r=
2
7
cm;h=(19−2×
2
7
)cm=12cm
Also radius of hemisphere =
2
7
cm=rcm
Now,
volume of the solid = volume of the cylinder + volume of two hemisphere
{πr
2
h+2(
3
2
πr
3
)}cm
3
=πr
2
(h+
3
4r
)cm
3
=
⎩
⎪
⎨
⎪
⎧
7
22
×(
2
7
)
2
×(12+
3
4
×
2
7
)
⎭
⎪
⎬
⎪
⎫
cm
3
=
7
22
×
2
7
×
2
7
×
3
50
cm
3
=641.66cm
3
Surface area of the solid
=curved surface are of cylinder + surface area of two hemisphere
=(2πrh+2×2πr
2
)cm
2
=2πr(h+2r)cm
2
=2×
7
22
×
2
7
(12+2×
7
22
×
2
7
)cm
2
=(2×
7
22
×
2
7
×19)cm
2
=418cm
2
Explanation:
Very hard answer
PLEASE MARK ME AS BRANLIEST
Similar questions