Question

A solid in the form of a cone surmounted on hemisphere of the same radius. If the height of the cone is 24 cm and radius of the hemisphere is 7 cm ,find the volume and surface area of the solid

Answer 1

volume of solid = vol of cone + vol of hemisphere

vol of cone = 1232

$\frac{1}{3}\pi {r}^{2}h$

1/3×22/7×7×7×24=1232

vol of hemisphere =718.66

$\frac{2}{3}\pi {r}^{3}$

radius of hemisphere =7cm

2/3×22/7×7×7×7=718.66

vol of solid=1232cmcube+718.66cm cube=1940.66

total surface area

Answer 2

The volume and the surface area of solid are 1950.66 cubic.cm. and 858 sq.cm.

Step-by-step explanation:

A solid in the form of a cone surmounted on hemisphere of the same radius.

Radius of hemisphere = 7 cm

Height of cone = 24 cm

Radius of cone = 7 cm

Volume of solid =$\frac{1}{3} \pi r^2 h + \frac{2}{3} \pi r^3$

Volume of solid = $\frac{1}{3} \times \frac{22}{7} \times 7^2 (24) + \frac{2}{3} \times \frac{22}{7} \times 7^3=1950.66 cm^3$

Surface area of solid =$\pi r \sqrt{h^2+r^2}+2 \pi r^2 = \frac{22}{7} \times 7 \times \sqrt{24^2+7^2}+2 \times \frac{22}{7} \times 7^2=858 cm^2$

Hence The volume and the surface area of solid are 1950.66 cubic.cm. and 858 sq.cm.

#Learn more:

A solid is in the shape of hemisphere surmounted by a cone if the radius of the hemisphere and base radius of cone is 7 cm and height of cone is 3.5 CM find the volume of solid .​

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