Question

A solid in the form of a right cylinder with hemisphere at one end and cone at other end, the radius of common base is 8 cms, and trhe heights of cylinder and conical portions aqre 10 cms,6 cms, respectively, find total surface area of solid

Answer 1

Given Common diameter of cylinder , hemisphere and cone = 3.5 cm , So
Radius of cylinder , hemisphere and cone = 1.75 cm

And
Height of cylinder = 10 cm
And
Height of cone = 6 cm
And
π = 3.14
And

Volume of solid = Volume of cylinder + Volume of hemisphere + Volume of cone

We know
Volume of cylinder = πr²h
And
Volume of hemisphere = 2πr³
And
Volume of cone = 1/3πr²h
SO,
Volume of solid = 3.14 × (1.75)2× 10 + 2× 3.14 × ( 1.75)33 + 3.14 × ( 1.75)2 ×63

Volume of solid = 3.14 × 3.0625× 10 + 2× 3.14 × 5.3593753 + 3.14 × 3.0625 ×63

Volume of solid = 96.1625 + 33.6568753 + 3.14 × 3.0625 × 2

Volume of solid = 96.1625 + 11.2189583 + 19.2325

Volume of solid = 126.6139583 cm³