Question

A solid iron ball is dropped in mercury contained in a beaker.
i) Will the ball float or sink?
ii) What will be the apparent weight of the ball ?​

Answer 1

Answer:

(a) The ball will float because the density of ball (i.e. iron) is less than the density of mercury. (b) While floating, the apparent weight = 0.

Explanation:

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Answer 2

Answer:

1) The ball will float

2) The apparent weight of the ball will be zero.

Explanation:

1. Since the density of iron is less than that of mercury therefore, the buoyant force acting on the ball will be greater than it's weight and thus it will float in the medium. ( density of iron is : 7.87 g/ml. density of mercury : 13.5 g/mL)
2. While floating the weight of object gets cancelled out by the buoyant force acting on it, therefore it's apparent weight becomes zero.  

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