A solid iron cuboidal block of dimensions 4.4 m × 2.6 m × 1m is recast into ahollowcylindrical pipe of internal radius 30 cm and thickness 5 cm. find the lengthof the pip
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Internal radius, r = 30 cm
Thickness, w = 5 cm
External radius, R = 30 + 5 = 35 cm
Here volume of cuboid = volume of hollow cylinder
440 × 260 ×100 = π(R2 – r2)h
⇒ 440 × 260 × 100 = π(352 – 302)h
⇒ 440 × 260 × 100 = π(325)h
∴ h = 11200 cm = 112 m
Thickness, w = 5 cm
External radius, R = 30 + 5 = 35 cm
Here volume of cuboid = volume of hollow cylinder
440 × 260 ×100 = π(R2 – r2)h
⇒ 440 × 260 × 100 = π(352 – 302)h
⇒ 440 × 260 × 100 = π(325)h
∴ h = 11200 cm = 112 m
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