Question

A solid iron cylinder has total surface area of 1848 m^2.curved surface area is five - sixth if its total surface area . find radius and height of the iron cylinder​

Answer 1

Answer:

Step-by-step explanation:

t s a = 1848

C s a = 5/6 x 1848 = 1540

2 x 22/7 x r x h = 1540

R x h = 1540 x 7 / 2 x 22 = 245

Answer 2

Answer:

Step-by-step explanation:

TSA=1848 m^2

CSA=(5/6) the of TSA

TSA of a cylinder =2πr(h+r)

1848=2 x 22/7 x r x (h+r)

1848 ÷22/7÷2= r x(h+r)

294=r x (h+r) ------1

CSA = 5/6 ×1848

=1540

CSA of a cylinder = 2πrh

1540= 2×22/7×r×h

1540÷2÷22/7=r×h

245=r×h

245/r=h

Sub 245/r= h in 1

294=r(245/r +r)

294=245+2r

294-245=2r

49=2r

r=24.5

h=245/r

=245/24.5

=10

Radius =24.5 m

Height=10m