Question

A solid iron pole consists of a cylinder of height 210cm and radius is 21 CM which is surmounted by another cylinder of height 70 cm and radius 7 cm find the volume of pole​
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Answer 1

Answer:

Height (h

1

) of larger cylinder =220 cm

Radius (r

1

) of larger cylinder =

2

24

=12 cm

Height (h

2

) of smaller cylinder = 60 cm

Radius (r

2

) of smaller cylinder =8 cm

Total volume of pole = Volume of larger cylinder + Volume of smaller cylinder

=πr

1

2

h

1

+πr

2

2

h

2

=(π(12)

2

×220)+(π(8)

2

×60)

=π[144×220+64×60]

=3.14[31,680+3,840]

=3.14×35520=111,532.8 cm

3

Mass of 1 cm

3

iron = 8 g

Mass of 111532.8 cm

3

iron = 11532.8×8=892262.4 g

solution

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Video Explanation

Answer 2

Step-by-step explanation:

Giv

a solid pole consists of to cylinder.

dimension of first cylinder

height - 210 cm

radius -21 cm

dimension of second cylinder

height - 70cm

radius - 7cm

we need to find out the volume of pole so firstly find out the volume of two cylinders and there after add the volume of cylinder

volume of a first cylinder

• 22/7 ×21×21 × 210
• 22×3×21×210
• 291060 cm

volume of second cylinder

• 22/7 ×7 ×7 ×70
• 22 ×7 × 70
• 10780

volume of pole = volume up first cylinder + volume of second cylinder

volume of pole = 291060 + 10780 =301840 cm