Question

A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass. [Use π = 3.14]

Answer 1

Vol=3.14*144*120 + 3.14*64*60=66316.8cm3
Mass=530534.4g

Answer 2

Solution :-

Diameter of larger cylinder = 24cm

Radius of larger cylinder = 24/2 = 12cm

Height of the larger cylinder = 220 cm

Volume of the larger cylinder = πr²h

=> 3.14 × 12 × 12 × 220 cm³

=> 3.14 × 144 × 220 cm³

=> 99475.2 cm³

Radius of the smaller cylinder = 8 cm

Height of the smaller cylinder = 60 cm

volume of the smaller cylinder = πr²h

=> 3.14 × 8 × 8 × 60

=> 3.14 × 64 × 60

=> 12057.6 cm³

Volume of the iron pole :-

volume of smaller + volume of larger cylinder

=> 99475.2 cm³ + 12057.6 cm³

=> 111532.8 cm³

Mass in iron of 1 cm³ = 8g

Mass in iron of 111532.8 cm³ = 111532.8 × 8

=> 892,262.4 gm

=> $\frac{892,262.4}{1000}$

=> 892.26 kg

Hence, The mass of the iron pole is 892.26kg.

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