A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass. [Use π = 3.14]
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Vol=3.14*144*120 + 3.14*64*60=66316.8cm3
Mass=530534.4g
Mass=530534.4g
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Solution :-
Diameter of larger cylinder = 24cm
Radius of larger cylinder = 24/2 = 12cm
Height of the larger cylinder = 220 cm
Volume of the larger cylinder = πr²h
=> 3.14 × 12 × 12 × 220 cm³
=> 3.14 × 144 × 220 cm³
=> 99475.2 cm³
Radius of the smaller cylinder = 8 cm
Height of the smaller cylinder = 60 cm
volume of the smaller cylinder = πr²h
=> 3.14 × 8 × 8 × 60
=> 3.14 × 64 × 60
=> 12057.6 cm³
Volume of the iron pole :-
volume of smaller + volume of larger cylinder
=> 99475.2 cm³ + 12057.6 cm³
=> 111532.8 cm³
Mass in iron of 1 cm³ = 8g
Mass in iron of 111532.8 cm³ = 111532.8 × 8
=> 892,262.4 gm
=>
=> 892.26 kg
Hence, The mass of the iron pole is 892.26kg.
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