Question

A solid iron pole consists of a cylinder of height 220cm,base is 24cm,which is surmounted by another cylinder of height 60 cm and radius 8cm. find the mass of the pole ,given that 1cm cube of iron has appears 8g of mass​

Answer 1

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A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8g mass. (Use = 3.14)

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

From the figure we have

Height (h1) of larger cylinder = 220cm

Radius (r1) of larger cylinder = = 12cm

Height (h2) of smaller cylinder = 60cm

Radius (r2) of smaller cylinder = 8cm

Mass of 1 cm3 iron = 8 gm

Mass of 111532.8 cm3 iron = 111532.8 x 8

= 892262.4 gm = 892.262 kg

Step-by-step explanation:

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Answer 2

Figure:-

Given:-

• A solid cylinder of height 220cm and base is 24cm,
• A cylinder of height 60 cm and radius 8cm.

To find:-

• find the mass of the pole of iron is..?

Solutions:-

• Height (h1) of larger cylinder = 220cm
• Radius (r1) of larger cylinder = 24/2 = 12cm

• Height (h2) of larger cylinder = 60cm
• Radius (r2) of larger cylinder = 8cm

Total volume of pole = Volume of larger cylinder + Volume of smaller cylinder

=> π(r1)²h1 + π(r2)²h2

=> π(12)² × 220 + π(8)² × 60

=> π[144 × 220 + 64 × 60]

=> π[35520]

=> 3.14 × 35520

=> 111532.8cm³

Mass of 1cm iron = 8g

Mass of 111532.8 cm³ iron

=> 111532.8 × 8

=> 892262.4g

=> 892.262kg

Hence, the mass of the pole of iron is 892.262kg.

Some Important:-

• Volume of cylinder ( Area of base × height ). = (πr²) × h

= πr²h

• Curved surface = ( Perimeter of base ) × height.

= (2πr) × h

= 2πrh

• Total surface are = Area of circular ends + curved surface area.

= 2πr² + 2πrh

= 2πr(r + h)

Where,

r = radius of the circular base of the cylinder.

h = height of cylinder.