A solid iron pole consists of aa cylinder of height 220cm and diameter 12 cm . which is surmounted by another cylinder of height 60 cm and radius 8 cm find the mass of the pole given that 1 cm^3 of iron has approximately 8g mass use pie = 3.14
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AKHIL234:
Bhaiya diameter 12cm diya hai
radius rakho
r =6 ayega
bhaiya diameter 24 hi diya h
Answered by
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Diameter of 1 cylinder=12cm
r=12/2
r=6cm
and h=220cm
now, R=8 in 2 cylinder
height H= 60cm
now, volume of 1 cylinder+volume of 2 cylinder
surface of cylinder=πr^2h+πR^2H
=π(r^2h+R^2H)
=3.14(6*6*220+8*8*60)
=3.14(7920+3840)
=39,926.4cm^3
now 1 cm^3 8g=39,926.4*8
=295,411.2gram/cm^3
r=12/2
r=6cm
and h=220cm
now, R=8 in 2 cylinder
height H= 60cm
now, volume of 1 cylinder+volume of 2 cylinder
surface of cylinder=πr^2h+πR^2H
=π(r^2h+R^2H)
=3.14(6*6*220+8*8*60)
=3.14(7920+3840)
=39,926.4cm^3
now 1 cm^3 8g=39,926.4*8
=295,411.2gram/cm^3
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