Question

A solid iron rectangular block of dimensions 4.4 m × 2.6 m  × 1 m is cast into a hollow cylindrical pipe of internal radius 30 cm and thickness 5 cm. Find the length of the pipe.

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Answer 1

Answer:

Step-by-step explanation:

Given that:

Internal radius r=30 cm

Thickness w=5 cm

External radius R=30+5=35 cm

Let the length of pipe be h.

Here,

The volume of cuboid = Volume of a hollow cylinder

 440×260×100=π(R2-r2)h

 

⇒440×260×100=π(square of 35 - square of 30)h

⇒440×260×100=π(325)h

⇒h=11204

The length of the pipe h=11204 cm=112.04 m

Answer 2

Answer:

Given that:

Internal radius r=30 cm

Thickness w=5 cm

External radius R=30+5=35 cm

Let the length of pipe be h.

Here,

The volume of cuboid = Volume of a hollow cylinder

440×260×100=π(R

2

–r

2

)h

⇒440×260×100=π(35

2

–30

2

)h

⇒440×260×100=π(325)h

⇒h=11204

The length of the pipe h=11204 cm=112.04 m