Question

A solid iron rectangular block of dimensions 4.4 m, 2.6 m and 1 m
is cast into a hollow cylindrical pipe of internal radius 30 cm and
thickness 5 cm. Find the length of the pipe.​

Answer 1

ɢɪᴠᴇɴ :-

★ Thickness = 5 cm

★ Internal radius = 30 cm

Hence,

★ External radius = Internal radius + Thickness

= (30 + 5) cm

ᴛᴏ ғɪɴᴅ:-

★ Length of the pipe

sᴏʟᴜᴛɪᴏɴ :-

Let the length of pipe be H.

According to the question, we can write __

Volume of a hollow cylinder = Volume of cubic cylinder

⟹ π (R²-r²)H = 4.4 *2.6*1

⟹ π (R² -r²) H = 440 *260 *100 [ in cm]

⟹ H = 11204 cm

⟹ H = 112.04 m

Hence,

the length of the pipe = 112.04 m

$\bold\blue{Thanks...!! }$

Answer 2

Given :

• Internal radius (r) = 30 cm.

• Thickness (w) = 5 cm.

• External radius (R) = 30 + 5 = 35 cm.

To Find :

• Find the length of the pipe = ?

Procedure :

Let the the length of the pipe be h.

The Volume of cuboid = Volume of hollow cylinder

➩ 440 × 260 × 100 = π (R² - r²)h

➩ 440 × 260 × 100 = π (35² - 30²)h

➩ 440 × 260 × 100 = π (325)h

➩ h = 11200 cm

➩ h = 112 m

Hence, the length of the pipe is 112 m.