Question

A solid iron rectangular block of dimensions 4.4m, 2.6m and 1m is cast into a hollow cylindrical pipe of internal radius 30cm and thickness 5 cm. Find the length of the pipe .​

Answer 1

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Given :

• Dimensions of a solid iron rectangular block = 4.4m, 2.6m and 1m

• Is being casted into a hollow cylindrical pipe of internal radius 30cm and thickness 5cm.

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To find :

Length of the pipe

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Volume of iron = (440 × 260 × 100) cm³

Internal radius of the pipe = 30cm

External radius of the pipe = (30 + 5) cm = 35cm

Let the length of the pipe be h cm

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Volume of iron in pipe

= = > (external volume - internal volume)

= = > [π(35)²h - π(30)²h] cm³

= = > πh[(35)² - (30)²] cm³

= = > (325πh) cm³

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Therefore

325πh = 430 × 260 × 100

= = > length = h cm

= = > {(440 × 260 × 100 × 7) / (325 × 22)}

= = > 11200 cm

= = > 112 m

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Answer 2

Given that:

Internal radius r=30 cm

Thickness w=5 cm

External radius R=30+5=35 cm

Let the length of pipe be h.

Here,

Here,The volume of cuboid = Volume of a hollow cylinder

440×260×100=π(R 2–r 2 )h

⇒440×260×100=π(35² –30² )h

⇒440×260×100=π(325)h

⇒h=11204

The length of the pipe h=11204 cm=112.04 m

HOPE IT HELPS..........