Question

A solid iron rod has a cylinder ical shape height is 11cm and base diameter is 7cm find the total volume of 50 rods​

Answer 1

Given :

• Height of a solid iron rod = 11 cm
• Base diameter of the solid iron rod = 7 cm

To find :

• Total volume of 50 rods

Concept :

To find the volume of 50 rods :-

• Firstly, calculate the radius of the iron rod.
• Then find the volume of the iron rod using the formula to calculate volume of cylinder.
• To find the volume of 50 such rods multiply the volume of 1 iron rod by 50, the resultant value will be our required answer.

➳ Formula to calculate radius :-

• Radius = Diameter ÷ 2

➳ Formula to calculate volume of cylinder :-

• Volume of cylinder = πr²h

where,

• Take π = 22/7
• r = radius
• h = height

Solution :

Radius of the iron rod :-

⇒ Radius = Diameter ÷ 2

⇒ Radius = 7 ÷ 2

⇒ Radius = 3.5

Radius of the iron rod = 3.5 cm

Volume of the iron rod :-

⇒ Volume = πr²h

⇒ Volume = 22/7 × (3.5)² × 11

⇒ Volume = 22/7 × 3.5 × 3.5 × 11

⇒ Volume = 22 × 0.5 × 3.5 × 11

⇒ Volume = 423.50

Volume of one iron rod = 423.50 cm³

Volume of 50 iron rods = Volume of one iron rod × 50

⇒ Volume of 50 iron rods = 423.50 × 50

⇒ Volume of 50 iron rods = 21,175

Answer → Volume of 50 iron rods = 21,175 cm³

Answer 2

GIVEN :-

• Height of cylindrical rod = 11cm
• Diameter of base of rod = 7 cm

TO FIND :-

• Total volume of 50 rods.

FORMULAE TO BE USED :-

• Radius = Diameter/2
• Volume of cylinder = πr²h

SOLUTION :-

• Diameter of cylinder = 7cm
• Radius = D/2 = 7/2

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎= 3.5cm

Substituting values in formula of volume of cylinder :-

● Volume = πr²h

↪ Volume = 22/7 × (3.5)² × 11

↪ Volume = 22/7 × 12.25 × 11

↪ Volume = 423.5 cm³

Volume of one rod = 423.5 cm³

Volume of 50 rods = 423.5 × 50

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎= 21,175 cm³

∴ , volume of 50 rods = 21 ,175 cm³