Question

A solid iron rod has a cylinderical shape. Its height is 11 cm. and base diameter is 7cm
Then find the total volume of 50 rods?​

Answer 1

Answer:

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Step-by-step explanation:

Answer: The volume of 50 rod is 21,155.75 cm³

Step-by-step explanation:

Since, The volume of a cylinder is,

V=\pi r^2hV=πr

2

h

Where r is the radius of the cylinder and h is the height.

Here, the diameter of one cylinder = 7 cm,

⇒ Radius of one cylinder, r = 7/2 = 3.5 cm

And, the height of a cylinder, h = 11 cm,

⇒ The volume of 1 cylinder,

V=\pi (3.5)^2(11)=3.14\times 12.25\times 11 = 423.115\text{ cube cm}V=π(3.5)

2

(11)=3.14×12.25×11=423.115 cube cm

⇒ The volume of 50 cylinder = 50 × 423.115

= 21,155.75 cm³

Answer 2

Answer:

cylindrical shape height h = 11 cm

Base diameter = 7cm

Radius = 7/2

= 3.5 cm

Step 2: Find the volume of the cylindrical shape iron rod

Volume of the cylinder = \pi r^2 h πr

2

h

= \frac{22}{7} * (3.5)^2 * 11

7

22

∗(3.5)

2

∗11

= 423.5 cm^3

3423.5cm

Step 3: Calculating the total volume of 50 rods

Volume of the one rod(cylinder) = 423.5 cm^3423.5cm

3

Total volume of the 50 rods = 50 * 423.5 cm^350∗423.5cm

3

= 21175 cm^3 21175cm

3