a solid is composed of a cylinder with hemispherical ends if the whole length of the solid is 184 cm and the radius of each of its hemispherical ends is 7 cm find the cost of polishing its surface area at the rate of rupees 10dmsquare
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A :- Radius of hemisphere=36/2=18
In the given solid height of cylinder = 108 - 2{radius of hemisphere}
= 108 - 18 = 90
CSA of the solid = CSA of cylinder + CSA of both hemispheres
= 2*22/7*18*90 + 2 (2*22/7*18*18) = 14256 cm^2
Cost = 14256 *70 = Rs 9980
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