A solid is composed of a cylinder with hemispherical ends if the whole length of solid is 114cm and the radius of each hemispherical end is 7cm then find the cost of polishing surface at the rate of ruppes 2 per dm square
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Step-by-step explanation:
A solid is composed of a cylinder with hemispherical ends. If the whole lengthe of the solid is 104 cm and the radius of each hemispherical end is 7 ...
wrong answer
Hemispherical part: r=7cm
Cylindrical part: r=7cm,h=104−(7+7)=90cm
Total surface area of the solid= CSA of cylindricall part+2×CSA of hemispherical part
=2πrh+2×2πr2=2πr(h+2r)
=2×722×7[90+2(7)]cm2
=44×104cm2=4576cm2
∴ TSA of the solid=4.576cm2
Cost of polishing at the rate of Rs.4 per 100cm2
=4576×100Rs.4=Rs.183.04
∴ Cost of polishing the solid=Rs.183.04.
Cylindrical part: r=7cm,h=104−(7+7)=90cm
Total surface area of the solid= CSA of cylindricall part+2×CSA of hemispherical part
=2πrh+2×2πr2=2πr(h+2r)
=2×722×7[90+2(7)]cm2
=44×104cm2=4576cm2
∴ TSA of the solid=4.576cm2
Cost of polishing at the rate of Rs.4 per 100cm2
=4576×100Rs.4=Rs.183.04
∴ Cost of polishing the solid=Rs.183.04.
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Answer
AnswerRs.183.04.
Explanation
Hemispherical part: r=7cm
Cylindrical part: r=7cm,h=104−(7+7)=90cm
Total surface area of the solid= CSA of cylindricall part+2×CSA of hemispherical part
=2πrh+2×2πr
2
=2πr(h+2r)
=2×
7
22
×7[90+2(7)]cm
2
=44×104cm
2
=4576cm
2
∴ TSA of the solid=4.576cm
2
Cost of polishing at the rate of Rs.4 per 100cm
2
=4576×
100
Rs.4
=Rs.183.04
∴ Cost of polishing the solid=Rs.183.04.
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