Question

A solid is composed of a cylinder with hemispherical ends .If the whole length of the solid is 104 cm and the radius of each hemispherical end is 7 cm , then find the cost of polishing its surface at the rate of rs.2 per 〖cm〗^2

Answer 1

Answer:

Rs 183.04.

Step-by-step explanation:

Hemispherical part: r=7cm

Cylindrical part: r=7cm,h=104−(7+7)=90cm

Total surface area of the solid= CSA of cylindricall part+2×CSA of hemispherical part

=2πrh+2×2πr2=2πr(h+2r)

=2×722×7[90+2(7)]cm2

=44×104cm2=4576cm2

∴ TSA of the solid=4.576cm2

Cost of polishing at the rate of Rs.4 per 100cm2

=4576×100Rs.4=Rs.183.04

∴ Cost of polishing the solid=Rs.183.04.

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