A solid is composed of a cylinder with hemispherical ends. If the total height of the solid is 105
cm and the radius of the hemispherical ends is 14 cm, find the cost of polishing the surface of the solid
at the rate of ₹ 0.1 per square cm.
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Answer:
Hemispherical part: r=7cm
Cylindrical part: r=7cm,h=104−(7+7)=90cm
Total surface area of the solid= CSA of cylindricall part+2×CSA of hemispherical part
=2πrh+2×2πr^2
=2πr(h+2r)
=2× 22 /7 ×7[90+2(7)]cm^2
=44×104cm^2
=4576cm ^2
∴ TSA of the solid=4.576cm^2
Cost of polishing at the rate of Rs.4 per 100cm^2
=4576× Rs.4 /100
=Rs.183.04
∴ Cost of polishing the solid=Rs.183.04.
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