Math, asked by umashri, 4 months ago

A solid is in the form of a cylinder with hemispherical ends. The

total height of the solid is 16 cm and the diameter of the cylinder

is 6 cm. Find the total volume of the solid.​

Answers

Answered by fenisebastian
1

ANSWER

ANSWERVolume of solid=πr

ANSWERVolume of solid=πr 2

ANSWERVolume of solid=πr 2 h+2×

ANSWERVolume of solid=πr 2 h+2× 3

ANSWERVolume of solid=πr 2 h+2× 32

ANSWERVolume of solid=πr 2 h+2× 32

ANSWERVolume of solid=πr 2 h+2× 32 πr

ANSWERVolume of solid=πr 2 h+2× 32 πr 3

ANSWERVolume of solid=πr 2 h+2× 32 πr 3

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 3

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]=

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 7

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 ×

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 2

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 ×

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 2

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×2

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 3

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5×

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 3

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 350

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 350

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 350

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 350 =641.67cm

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 350 =641.67cm 3

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 350 =641.67cm 3

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 350 =641.67cm 3 TSA of solid=2πrh+2×2πr

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 350 =641.67cm 3 TSA of solid=2πrh+2×2πr 2 =2πr(h+2r)

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 350 =641.67cm 3 TSA of solid=2πrh+2×2πr 2 =2πr(h+2r)=2×

ANSWERVolume of solid=πr 2 h+2× 32 πr 3 =πr 2 [h+ 34r ]= 722 × 27 × 27 [(19−7)+ 3×24×7 ]=38.5(12+ 314 )=38.5× 350 =641.67cm 3 TSA of solid=2πrh+2×2πr 2 =2πr(h+2r)=2× 722 2

27[(19−7)+2×

27[(19−7)+2× 2

27[(19−7)+2× 27=22(12+7)=22×19

27[(19−7)+2× 27=22(12+7)=22×19=418cm

27[(19−7)+2× 27=22(12+7)=22×19=418cm 2

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