Question

A solid is in the form of a right circular cone mounted on a hemisphere the radius of the hemisphere is 3.5 cm and the height of the cone is 4 centimetre the solid is placed in a cylindrical vessel full of water in such a way that the whole solid is submerged in water if the radius of the cylindrical vessel is 5 cm and its height is 10.5 cm find the volume of water left in the cylindrical vessel

Answer 1

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Answer 2

Answer:

251.690 cubic cm

Step-by-step explanation:

Radius of hemisphere R = 3.5 m

Height of cone H = 4 cm

Radius of cone R = 3.5 m

Radius of cylinder r = 5 cm

Height of cylinder  h = 5 cm

A solid is in the form of a right circular cone mounted on a hemisphere the solid is placed in a cylindrical vessel full of water in such a way that the whole solid is submerged in water So, find the volume of water left in the cylindrical vessel

Volume of water left = Volume of cylinder - (Volume of Cone+Volume of hemisphere)

$\text{Volume of water left}=\pi r^2 h-(\frac{1}{3} \pi R^2H+\frac{2}{3}\pi R^3)$

$\text{Volume of water left}=\frac{22}{7} \times (5)^2 (5)-(\frac{1}{3} \times \frac{22}{7} \times (3.5)^2 (4)+\frac{2}{3} \times \frac{22}{7} \times 3.5^3)$

$\text{Volume of water left}=251.690 cm^3$

Hence the volume of water left in the cylindrical vessel is $251.690 cm^3$