Question

A solid is in the form of a right circular cylinder with hemispherical ends the total height

Answer 1

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Question :
A solid is in the form of right circular cylinder with hemispherical ends. The total height of the solid is 58cm and the diameter of the cylinder is 28cm. find the total surface area of the solid.


Given :

Total height of solid= 58 cm

Diameter of Cylinder= 28 cm

Radius of Cylinder = radius of hemisphere= 28/2= 14 cm

Radius of Cylinder & hemisphere (r)= 14 cm

Height of hemisphere= radius of hemisphere= 14cm

Height of 2 hemisphere= 2× 14= 28cm

Height of Cylinder= Total height of solid - Height of 2 hemisphere

Height of Cylinder(h)= 58 - 28 = 30 cm

Total surface area of the solid= surface area of cylinder + surface area of two hemispheres

Total surface area of the solid= 2πrh + 2(2πr²)

Total surface area of the solid=2πrh + 4πr²

Total surface area of the solid= 2πr(h+2r)

Total surface area of the solid= 2×(22/7)×14(30+2×14)

= 2× 22×2(30+28)

= 88 × 58

Total surface area of the solid= 5104 m²

Hence, Total surface area of the solid= 5104 m².

Answer 2

Answer:

total height of solid =58cm

diameter of cylinder =28cm

radius of cylinder =radius of hemisphere =28/2=14cm

total surface area of solid =curved surface area of cyclinder+curved surface area of hemisphere

2*22/7*14*58 +2*22/7*14*14

5,104 +1232

=6,336